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Given `n`

>= 0, create an array with the pattern {1, 1, 2, 1, 2, 3, ... 1, 2, 3 .. `n`

} (spaces added to show the grouping). Note that...

Given `n`

>= 0, create an array with the pattern {1, 1, 2, 1, 2, 3, ... 1, 2, 3 .. `n`

} (spaces added to show the grouping). Note that the length of the array will be 1 + 2 + 3 ... + `n`

, which is known to sum to exactly `n * (n + 1)/2`

.

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