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Given two strings, base
and remove
, return a version of the base
string where all instances of the remove
string have been removed (not...
Given two strings, base
and remove
, return a version of the base
string where all instances of the remove
string have been removed (not case sensitive). You may assume that the remove
string is length 1 or more. Remove only non-overlapping instances, so with "xxx" removing "xx" leaves "x".
Examples:
withoutString("Hello there", "llo") -> "He there"
withoutString("Hello there", "e") -> "Hllo thr"
withoutString("Hello there", "x") -> "Hello there"
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