X462: Find Largest Shape

For the question below, assume the following implementation of the Measurable interface and Square and Circle classes:

​x
 
public class Shape {
​
}
​
public class Circle extends Shape
{
   private double radius;
​
​
   public Circle(double newRadius)
   {
      radius = newRadius;
   } // end constructor
​
   public double getRadius() {
       return radius;
   }
​
​
   public double getCircumference()
   {
      return 2.0 * Math.PI * radius;
   } // end getCircumference
​
   public double getPerimeter() // Measurable interface
   {
      return getCircumference();
   } // end getPerimeter
​
   public double getArea()      // Measurable interface
   {
      return Math.PI * radius * radius;
   } // end getArea
​
} // end Circle
​
public class Square extends Shape  {
​
    private double side;
​
    public Square(double len) {
        side = len;
    }
​
    public double getSide() {
        return side;
    }
​
    public double getPerimeter() {
        return 4 * side;
    }
​
    public double getArea() {
        return side * side;
    }
​
}

Write a method that takes in two variables: one of type Square, one of type Circle. This code should assign the object with the larger area the variable max defined below, then return max. The two shapes will never have the same Area.

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