For this question, assume the following implementation of a singly linked list:
public class SLList<T> implements Iterable<T>...
For this question, assume the following implementation of a singly linked list:
public class SLList<T> implements Iterable<T> {
private int numberOfEntries;
private Node<T> head;
public SLList() {
head = null;
this.numberOfEntries = 0;
}// end default constructor
public boolean isEmpty() {
return numberOfEntries == 0;
}
public int getNumberOfEntries() {
return numberOfEntries;
}
public void clear() {
head = null;
this.numberOfEntries = 0;
}
@Override
public Iterator<T> iterator() {
return new SLListIterator();
}
...
//Node
private class Node<E> {
private E data; // Entry in bag
private Node<E> next; // Link to next node
public Node(E dataPortion) {
this(dataPortion, null);
} // end constructor
public Node(E dataPortion, Node<E> nextNode) {
data = dataPortion;
next = nextNode;
}
public E getData() {
if (data != null) {
return data;
}
return null;
}
public Node<E> getNext() {
return next;
}
public void setNext(Node<E> newNext) {
next = newNext;
}
} // end Node
//Iterator
// Iterator
public class SLListIterator implements Iterator<T> {
private Node<T> current;
private boolean canRemove;
public SLListIterator() {
if (head != null) {
current = head;
}
canRemove = false;
}
@Override
public boolean hasNext() {
return current != null;
}
@Override
public boolean next() {
...
}
}//end iterator
}
Implement the remove()
method in the Iterator class. Check the javadocs if you need help remembering what this method is supposed to do!
You can find documentation for the Iterators at: https://docs.oracle.com/javase/8/docs/api/java/util/Iterator.html
Remember, that next()
must be called before remove can run without error.
For example, consider a singly linked list that looks like this:
A --> B --> C --> D --> E --> null
^
|
Current
Running next()
should change the state to look like this:
A --> B --> C --> D --> E --> null
^
|
Current
Running remove()
at this point, should remove A
from the chain and leave the list looking like this:
B --> C --> D --> E --> null
^
|
Current
When writing this code, consider how you would remove other letters from this chain like D
or E
!
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