X96: roundSum

For this problem, we'll round an int value up to the next multiple of 10 if its rightmost digit is 5 or more, so 15 rounds up to 20. Alternately, round down to the previous multiple of 10 if its rightmost digit is less than 5, so 12 rounds down to 10. Given 3 ints, a, b, and c, return the sum of their rounded values. To avoid code repetition, write a separate helper public int round10(int num) and call it 3 times. Write the helper entirely below and at the same indent level as roundSum().

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